Subtree of Another Tree

572. Subtree of Another Tree

Difficulty: Easy

Related Topics: Tree, DFS, String Matching, Binary Tree, Hash Function

Given the roots of two binary trees root and subRoot, return true if there is a subtree of root with the same structure and node values of subRoot and false otherwise.

A subtree of a binary tree tree is a tree that consists of a node in tree and all of this node’s descendants. The tree tree could also be considered as a subtree of itself.

Example 1:

Input: root = [3,4,5,1,2], subRoot = [4,1,2] Output: true

Example 2:

Input: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2] Output: false

Code:

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def isSubtree(self, root: Optional[TreeNode], subRoot: Optional[TreeNode]) -> bool:
        if not root: return False
        if self.isSameTree(root, subRoot):
            return True
        return self.isSubtree(root.left, subRoot) or self.isSubtree(root.right, subRoot)

    def isSameTree(self, root, subRoot) -> bool:
        if root and subRoot:
            return root.val == subRoot.val and self.isSameTree(root.left, subRoot.left) and self.isSameTree(root.right, subRoot.right)
        return root is subRoot